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Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 15 September 2010 and 24 September 2010.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2010

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
other: Testing was conducted using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008, and Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.
Deviations:
no
Principles of method if other than guideline:
The vapour pressure was determined using a vapour pressure balance with measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008, and Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Reference substance name:
X-3383
IUPAC Name:
X-3383
Details on test material:
Sponsor's identification: X-3383
Description : pale yellow viscous liquid
Batch number : not supplied
Label : INVENTORY NO: X-3383
Date received : 10 August 2010
Expiry date : 06 August 2016
Storage conditions: room temperature in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0.013 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Run 1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

40

313.15

0.003193358

39.73

3.973E-08

0.055155419

-1.258411814

41

314.15

0.003183193

39.16

3.916E-08

0.054364113

-1.264687696

42

315.15

0.003173092

40.36

4.036E-08

0.056030020

-1.251579221

43

316.15

0.003163056

46.18

4.618E-08

0.064109671

-1.193076450

44

317.15

0.003153082

51.90

5.190E-08

0.072050497

-1.142363021

45

318.15

0.003143171

51.29

5.129E-08

0.071203660

-1.147497680

46

319.15

0.003133323

60.87

6.087E-08

0.084503155

-1.073127077

47

320.15

0.003123536

64.21

6.421E-08

0.089139931

-1.049927709

48

321.15

0.003113810

71.95

7.195E-08

0.099885033

-1.000499580

49

322.15

0.003104144

73.59

7.359E-08

0.102161774

-0.990711576

50

323.15

0.003094538

87.34

8.734E-08

0.121250296

-0.916317191

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3598.897
Standard deviation in slope     212.846

Intercept                                        10.196
Standard deviation in intercept    0.669

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3598.897/temp(K) + 10.196

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.875.

Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

40

313.15

0.003193358

38.72

3.872E-08

0.053753280

-1.269595030

41

314.15

0.003183193

38.77

3.877E-08

0.053822693

-1.269034578

42

315.15

0.003173092

36.28

3.628E-08

0.050365935

-1.297863100

43

316.15

0.003163056

43.00

4.300E-08

0.059695017

-1.224061923

44

317.15

0.003153082

48.03

4.803E-08

0.066677945

-1.176017792

45

318.15

0.003143171

51.55

5.155E-08

0.071564607

-1.145301709

46

319.15

0.003133323

53.10

5.310E-08

0.073716404

-1.132435858

47

320.15

0.003123536

60.24

6.024E-08

0.083628553

-1.077645416

48

321.15

0.003113810

63.30

6.330E-08

0.087876617

-1.056126669

49

322.15

0.003104144

71.11

7.111E-08

0.098718898

-1.005599700

50

323.15

0.003094538

78.91

7.891E-08

0.109547297

-0.960398335

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3364.470
Standard deviation in slope     248.559

Intercept                                          9.429
Standard deviation in intercept    0.781

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3364.470/temp(K) + 9.429

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.855.

Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

40

313.15

0.003193358

34.03

3.403E-08

0.047242358

-1.325668430

41

314.15

0.003183193

35.89

3.589E-08

0.049824515

-1.302556920

42

315.15

0.003173092

39.15

3.915E-08

0.054350230

-1.264798612

43

316.15

0.003163056

40.93

4.093E-08

0.056821326

-1.245488634

44

317.15

0.003153082

47.77

4.777E-08

0.066316999

-1.178375137

45

318.15

0.003143171

50.58

5.058E-08

0.070217999

-1.153551554

46

319.15

0.003133323

53.53

5.353E-08

0.074313354

-1.128933135

47

320.15

0.003123536

57.44

5.744E-08

0.079741436

-1.098315947

48

321.15

0.003113810

67.13

6.713E-08

0.093193639

-1.030613732

49

322.15

0.003104144

71.48

7.148E-08

0.099232553

-1.003345835

50

323.15

0.003094538

73.81

7.381E-08

0.102467190

-0.989415173

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3609.983
Standard deviation in slope     123.440

Intercept                                        10.191
Standard deviation in intercept    0.388

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3609.983/temp(K) + 10.191

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.916.

Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

40

313.15

0.003193358

34.90

3.490E-08

0.048450141

-1.314704952

41

314.15

0.003183193

32.99

3.299E-08

0.045798572

-1.339148063

42

315.15

0.003173092

39.56

3.956E-08

0.054919415

-1.260274096

43

316.15

0.003163056

47.79

4.779E-08

0.066344764

-1.178193348

44

317.15

0.003153082

45.53

4.553E-08

0.063207305

-1.199232728

45

318.15

0.003143171

44.92

4.492E-08

0.062360468

-1.205090631

46

319.15

0.003133323

52.68

5.268E-08

0.073133337

-1.135884612

47

320.15

0.003123536

57.34

5.734E-08

0.079602610

-1.099072690

48

321.15

0.003113810

56.36

5.636E-08

0.078242119

-1.106559394

49

322.15

0.003104144

66.88

6.688E-08

0.092846575

-1.032234114

50

323.15

0.003094538

77.66

7.766E-08

0.107811976

-0.967332993

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3353.445
Standard deviation in slope     309.168

Intercept                                          9.374
Standard deviation in intercept    0.972

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3353.445/temp(K) + 9.374

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.873.

For Graphs of Log10Vapour Pressure vs Reciprocal Temperature for Runs 1 - 4 Please see Attachment 2.

Applicant's summary and conclusion

Conclusions:
The vapour pressure of the test item has been determined to be 1.3 x 10e-2 Pa at 25ºC.
Executive summary:

INTRODUCTION

Hazardous physico-chemical properties of the test item have been determined.

Methods employed are designed to be compatible with those specified in Commission Regulation (EC) No 440/2008 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties and the current OECD Guidelines for Testing of Chemicals.

Method

The vapour pressure was determined using a vapour pressure balance withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008, and Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

Run

Log10[Vp(25ºC)]

1

-1.875

2

-1.855

3

-1.916

4

-1.873

Mean

-1.880

Vapour Pressure

1.318 x 10-2Pa

The test item did not change in appearance under the conditions used in the determination.

Conclusion

The vapour pressure of the test item has been determined to be1.3 x 10-2Pa at 25ºC.