Tributyltin chloride

Vapour pressure

Link to relevant study record(s)

Reference

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

17 May 2010 and 05 June 2010

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

guideline study

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Remarks:

in compliance with UK GLP standards (Schedule 1, Good Laboratory Practice Regulations 1999 (SI 1999/3106 as amended by SI 2004/0994))

Type of method:

effusion method: vapour pressure balance

Key result

Temp.:

25 °C

Vapour pressure:

0.49 Pa

Table 1: Run 1

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
18	291.15	0.003434656	139.50	1.395E-07	0.193661740	-0.712956171
19	292.15	0.003422899	163.06	1.631E-07	0.226369056	-0.645182941
20	293.15	0.003411223	187.41	1.874E-07	0.260173094	-0.584737618
21	294.15	0.003399626	211.74	2.117E-07	0.293949367	-0.531727470
22	295.15	0.003388108	240.03	2.400E-07	0.333223135	-0.477264854
23	296.15	0.003376667	272.54	2.725E-07	0.378355344	-0.422100127
24	297.15	0.003365304	309.41	3.094E-07	0.429540350	-0.366996033
25	298.15	0.003354016	350.77	3.508E-07	0.486958627	-0.312507936
26	299.15	0.003342805	398.47	3.985E-07	0.553178447	-0.257134749
27	300.15	0.003331667	447.07	4.471E-07	0.620647699	-0.207154851
28	301.15	0.003320604	507.92	5.079E-07	0.705123088	-0.151735065

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4854.996
Standard deviation in slope           31.989

Intercept                                         15.971
Standard deviation in intercept       0.108

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -4854.996/temp(K) + 15.971

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.313.

Table 2: Run 2

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
18	291.15	0.003434656	145.55	1.456E-07	0.202060690	-0.694518169
19	292.15	0.003422899	165.38	1.654E-07	0.229589810	-0.639047391
20	293.15	0.003411223	190.47	1.905E-07	0.264421158	-0.577703797
21	294.15	0.003399626	215.77	2.158E-07	0.299544040	-0.523539317
22	295.15	0.003388108	243.71	2.437E-07	0.338331918	-0.470657029
23	296.15	0.003376667	274.78	2.748E-07	0.381465038	-0.418545260
24	297.15	0.003365304	311.19	3.112E-07	0.432011446	-0.364504746
25	298.15	0.003354016	351.62	3.516E-07	0.488138645	-0.311456809
26	299.15	0.003342805	397.40	3.974E-07	0.551693013	-0.258302516
27	300.15	0.003331667	448.13	4.481E-07	0.622119250	-0.206126360
28	301.15	0.003320604	507.25	5.073E-07	0.704192957	-0.152308323

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4728.317
Standard deviation in slope           17.188

Intercept                                         15.548
Standard deviation in intercept       0.058

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -4728.317/temp(K) + 15.548

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.311.

Table 3: Run 3

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
18	291.15	0.003434656	144.03	1.440E-07	0.199950540	-0.699077418
19	292.15	0.003422899	164.34	1.643E-07	0.228146024	-0.641787096
20	293.15	0.003411223	189.86	1.899E-07	0.263574322	-0.579096902
21	294.15	0.003399626	212.18	2.122E-07	0.294560200	-0.530825934
22	295.15	0.003388108	241.38	2.414E-07	0.335097281	-0.474829096
23	296.15	0.003376667	276.63	2.766E-07	0.384033312	-0.415631102
24	297.15	0.003365304	310.01	3.100E-07	0.430373304	-0.366154676
25	298.15	0.003354016	352.02	3.520E-07	0.488693947	-0.310963040
26	299.15	0.003342805	397.81	3.978E-07	0.552262198	-0.257854683
27	300.15	0.003331667	447.72	4.477E-07	0.621550065	-0.206523884
28	301.15	0.003320604	506.52	5.065E-07	0.703179530	-0.152933781

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4770.362
Standard deviation in slope           22.047

Intercept                                         15.688
Standard deviation in intercept       0.074

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -4770.362/temp(K) + 15.688

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.312.

 

Table 4: Run 4

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
18	291.15	0.003434656	146.46	1.465E-07	0.203324003	-0.691811349
19	292.15	0.003422899	164.35	1.644E-07	0.228159906	-0.641760670
20	293.15	0.003411223	188.79	1.888E-07	0.262088888	-0.581551392
21	294.15	0.003399626	215.77	2.158E-07	0.299544040	-0.523539317
22	295.15	0.003388108	241.78	2.418E-07	0.335652584	-0.474110005
23	296.15	0.003376667	273.83	2.738E-07	0.380146195	-0.420049352
24	297.15	0.003365304	309.76	3.098E-07	0.430026240	-0.366505043
25	298.15	0.003354016	349.39	3.494E-07	0.485042833	-0.314219908
26	299.15	0.003342805	395.21	3.952E-07	0.548652732	-0.260702454
27	300.15	0.003331667	444.95	4.450E-07	0.617704596	-0.209219168
28	301.15	0.003320604	505.70	5.057E-07	0.702041160	-0.153637425

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4711.040
Standard deviation in slope           19.150

Intercept                                         15.488
Standard deviation in intercept       0.065

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -4711.040/temp(K) + 15.488

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.313.

Conclusions:

The vapour pressure of the test material was determined to be 4.9 x 10^-1 Pa at 25 °C.

Executive summary:

The vapour pressure of the test material was determined by using a vapour pressure balance system. The study was GLP compliant and performed to EU Method A.4. The vapour pressure of the test material was determined to be 4.9 x 10 ^-1 Pa at 25 °C.

Description of key information

The vapour pressure of the test material was determined by using a vapour pressure balance system. The study was GLP compliant and performed to EU Method A.4. The vapour pressure of the test material was determined to tbe 4.9 x 10^-1 Pa at 25 °C.

Key value for chemical safety assessment

Vapour pressure:

0.49 Pa

at the temperature of:

25 °C

Additional information

Atwal SS et al (2010) was selected as the key study to fulfil the data requirement, as it was GLP compliant and performed to current internationally accepted guidelines. A reliability rating of 1 was assigned to this study, according to the criteria of Klimisch, 1997.

Supporting information is also available from a test material safety data sheet, Atofina Chemicals Inc. (2001).

A reliability rating of 4 was assigned to this study, according to the criteria of Klimisch, 1997 as this information is from a secondary source.

The vapour pressure for the test material is given as < 0.001 mm Hg at 20 °C.