Registration Dossier

Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
The study was conducted between 06 July 2007 and 17 August 2007.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2007
Report date:
2007

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Reference substance name:
Magenta T-43
IUPAC Name:
Magenta T-43
Test material form:
solid: particulate/powder
Details on test material:
Sponsor's identification: MAGENTA T-43
Description: dark red solid
Storage conditions: room temperature in the dark
Batch number: H186-5

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0.062 Pa

Any other information on results incl. tables

Results-Run 1

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

33

306.15

0.003266373

79.50

7.950E-08

0.110366368

-0.957163250

34

307.15

0.003255738

82.79

8.279E-08

0.114933731

-0.939552496

35

308.15

0.003245173

85.55

8.555E-08

0.118765318

-0.925310365

36

309.15

0.003234676

94.46

9.446E-08

0.131134681

-0.882282437

37

310.15

0.003224246

96.91

9.691E-08

0.134535908

-0.871161785

38

311.15

0.003213884

102.00

1.020E-07

0.141602132

-0.848930207

39

312.15

0.003203588

106.78

1.068E-07

0.148237997

-0.829040462

40

313.15

0.003193358

113.78

1.138E-07

0.157955790

-0.801464449

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (l/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

 

Slope = -2148.673

Standard deviation in slope: 94.129

Intercept: 6.058

Standard deviation in intercept: 0.304

 

The results obtained indicate the following vapour pressure relationship:

LoglO(Vp (Pa))=-2148.673/temp(K)+6.058.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.149.

 

 

Results-Run 2

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

32

305.15

0.003277077

69.63

6.963E-08

0.096664279

-1.014733984

33

306.15

0.003266373

72.07

7.207E-08

0.100051624

-0.999775857

34

307.15

0.003255738

73.45

7.345E-08

0.101967418

-0.991538579

35

308.15

0.003245173

76.42

7.642E-08

0.106090539

-0.974323345

36

309.15

0.003234676

79.92

7.992E-08

0.110949435

-0.954874904

37

310.15

0.003224246

85.34

8.534E-08

0.118473784

-0.926377740

38

311.15

0.003213884

90.01

9.001E-08

0.124956940

-0.903239617

39

312.15

0.003203588

95.63

9.563E-08

0.132758940

-0.876936223

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (l/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope: -1882.968

Standard deviation in slope: 128.834

Intercept: 5.146

Standard deviation in intercept: 0.417

 

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa))=-1882.968/temp(K)+5.146.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.170.

 

 

 

Results-Run 3

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

34

307.15

0.003255738

71.64

7.164E-08

0.099454674

-1.002374802

35

308.15

0.003245173

74.40

7.440E-08

0.103286261

-0.985957443

36

309.15

0.003234676

80.98

8.098E-08

0.112420987

-0.949152606

37

310.15

0.003224246

81.94

8.194E-08

0.113753713

-0.944034419

38

311.15

0.003213884

86.94

8.619E-08

0.119653802

-0.922073498

39

312.15

0.003203588

94.25

9.425E-08

0.130843147

-0.883249020

40

313.15

0.003193358

97.01

9.701E-08

0.134674734

-0.870713874

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (l/T(K)) for Run 3 gives the following statistical data usinganunweighted least squares treatment.

 

Slope: -2155.188

Standard deviation in slope: 144.407

Intercept: 6.012

Standard deviation in intercept: 0.466

 

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-2155. 188/temp(K)+6.012.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.216.

 

 

Results-Run 4

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

32

305.15

0.003277077

58.59

5.859E-08

0.081337931

-1.089706881

33

306.15

0.003266373

62.20

6.220E-08

0.086349536

-1.063739994

34

307.15

0.003255738

64.53

6.453E-08

0.089584172

-1.047768714

35

308.15

0.003245173

66.55

6.655E-08

0.092388450

-1.034382319

36

309.15

0.003234676

65.49

6.549E-08

0.090916898

-1.041355388

37

310.15

0.003224246

74.62

7.462E-08

0.103591678

-0.984675134

38

311.15

0.003213884

78.33

7.833E-08

0.108742108

-0.963602252

39

312.15

0.003203588

81.52

8.152E-08

0.113170645

-0.946266208

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (l/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -1911.617

Standard deviation in slope: 202.534

Intercept: 5.172

Standard deviation in intercept: 0.656

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-19l1.617/temp(K)+5.172.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.239.

Results-Run 5

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

33

306.15

0.003266373

60.82

6.082E-08

0.084433742

-1.073483963

34

307.15

0.003255738

61.77

6.177E-08

0.085752585

-1.066752777

35

308.15

0.003245173

65.91

6.591E-08

0.091499966

-1.038579067

36

309.15

0.003234676

71.43

7.143E-08

0.099163140

-1.003649729

37

310.15

0.003224246

71.75

7.175E-08

0.099607382

-1.001708473

38

311.15

0.003213884

74.83

7.483E-08

0.103883211

-0.983454634

39

312.15

0.003203588

79.92

7.992E-08

0.110949435

-0.954874904

40

313.15

0.003193358

84.17

8.417E-08

0.116849524

-0.932373052

 

A plot of Log10(vapour pressure (Pa» versus reciprocal temperature (l/T(K» for Run 5 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -1956.528

Standard deviation in slope: 117.017

Intercept: 5.312

Standard deviation in intercept: 0.378

The results obtained indicate the following vapour pressure relationship:

LoglO(Vp (Pa))=-1956.528/temp(K)+5.312.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.25

 

Results-Run 6

Temp. (°C)

Temp. (K)

Reciprocal Temp. (K-1)

Mass Difference

(µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

31

304.15

0.003287851

57.53

5.753E-08

0.079866379

-1.097636005

32

305.15

0.003277077

59.33

5.933E-08

0.082365240

-1.084256030

33

306.15

0.003266373

61.99

6.199E-08

0.086058002

-1.065208742

34

307.15

0.003255738

63.58

6.358E-08

0.088265329

-1.054209855

35

308.15

0.003245173

65.38

6.538E-08

0.090764190

-1.042085462

36

309.15

0.003234676

66.12

6.612E-08

0.091791500

-1.037197534

37

310.15

0.003224246

71.96

7.196E-08

0.099898916

-1.000439224

38

311.15

0.003213884

71.43

7.143E-08

0.099163140

-1.003649729

39

312.15

0.003203588

79.29

7.929E-08

0.110074834

-0.958311961

40

313.15

0.003193358

82.47

8.247E-08

0.114489489

-0.941234384

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (l/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope: -1593.300

Standard deviation in slope: 118.285

Intercept: 4.134

Standard deviation in intercept: 0.383

 

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-1593.300/temp(K)+4.134.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -1.210.

 

Overal Mean Results 

 

Run

Log10[Vp(25°C)]

1

-1.149

2

-1.170

3

-1.216

4

-1.239

5

-1.250

6

-1.210

 

Mean

-1.206

Vapour Pressure

6.2x 10-2Pa

  

 

The test material did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapour pressure of the test material has been determined to be 6.2 x E-02 Pa at 25°C.
Executive summary:

The vapour pressure of substance Magenta T-43 was determined to be 6.2 x E-02 Pa at 25 °C according to method A4 Commission Directive 92/69/EEC using the vapour pressure balance method.