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Physical & Chemical properties

Vapour pressure

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Link to relevant study record(s)

Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 09 June 2011 and 21 June 2011.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.
Qualifier:
equivalent or similar to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
Qualifier:
equivalent or similar to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance
Temp.:
25 °C
Vapour pressure:
0.001 Pa
Transition / decomposition:
no

Run 7

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

96

369.15

0.002708926

68.61

6.861E-08

0.095248258

-1.021142959

97

370.15

0.002701607

71.72

7.172E-08

0.099565735

-1.001890098

98

371.15

0.002694328

73.62

7.362E-08

0.102203421

-0.990534566

99

372.15

0.002687089

77.51

7.751E-08

0.107603738

-0.968172642

100

373.15

0.002679887

82.11

8.211E-08

0.113989716

-0.943134327

101

374.15

0.002672725

85.94

8.594E-08

0.119306738

-0.923335029

102

375.15

0.002665600

89.55

8.955E-08

0.124318343

-0.905464789

103

376.15

0.002658514

95.62

9.562E-08

0.132745058

-0.876981639

104

377.15

0.002651465

103.03

1.030E-07

0.143032036

-0.844566679

105

378.15

0.002644453

109.91

1.099E-07

0.152583239

-0.816493171

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope                                      -3144.046
Standard deviation in slope   127.857

Intercept                                         7.486
Standard deviation in intercept  0.342

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3144.046/temp(K) + 7.486

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.059.

Run 7 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 7 to 10.

Run 8

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

97

370.15

0.002701607

65.53

6.553E-08

0.090972429

-1.041090211

98

371.15

0.002694328

68.75

6.875E-08

0.095442614

-1.020257676

99

372.15

0.002687089

71.04

7.104E-08

0.098621720

-1.006027426

100

373.15

0.002679887

75.12

7.512E-08

0.104285806

-0.981774799

101

374.15

0.002672725

79.63

7.963E-08

0.110546841

-0.956453663

102

375.15

0.002665600

84.68

8.468E-08

0.117557535

-0.929749529

103

376.15

0.002658514

90.62

9.062E-08

0.125803777

-0.900306321

104

377.15

0.002651465

97.63

9.763E-08

0.135535453

-0.867947089

105

378.15

0.002644453

103.95

1.040E-07

0.144309232

-0.840705885

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

Slope                                      -3548.443
Standard deviation in slope   139.658

Intercept                                         8.535
Standard deviation in intercept  0.373

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3548.443/temp(K) + 8.535

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.366.

Run 8 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 7 to 10.

Run 9

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

96

369.15

0.002708926

58.71

5.871E-08

0.081504521

-1.088818298

97

370.15

0.002701607

61.87

6.187E-08

0.085891411

-1.066050263

98

371.15

0.002694328

64.91

6.491E-08

0.090111710

-1.045218770

99

372.15

0.002687089

68.22

6.822E-08

0.094706838

-1.023618664

100

373.15

0.002679887

71.27

7.127E-08

0.098941019

-1.004623620

101

374.15

0.002672725

76.03

7.603E-08

0.105549119

-0.976545388

102

375.15

0.002665600

80.95

8.095E-08

0.112379339

-0.949313526

103

376.15

0.002658514

85.71

8.571E-08

0.118987439

-0.924498884

104

377.15

0.002651465

90.12

9.012E-08

0.125109649

-0.902709196

105

378.15

0.002644453

97.69

9.769E-08

0.135618748

-0.867680269

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.

Slope                                      -3373.879
Standard deviation in slope     82.220

Intercept                                         8.042
Standard deviation in intercept  0.220

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3373.879/temp(K) + 8.042

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.270.

Run 9 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 7 to 10.

Run 10

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

97

370.15

0.002701607

56.76

5.676E-08

0.078797422

-1.103487992

98

371.15

0.002694328

60.22

6.022E-08

0.083600788

-1.077789628

99

372.15

0.002687089

63.08

6.308E-08

0.087571201

-1.057638694

100

373.15

0.002679887

67.43

6.743E-08

0.093610115

-1.028677219

101

374.15

0.002672725

70.74

7.074E-08

0.098205243

-1.007865323

102

375.15

0.002665600

75.98

7.598E-08

0.105479706

-0.976831090

103

376.15

0.002658514

80.65

8.065E-08

0.111962862

-0.950926007

104

377.15

0.002651465

86.19

8.619E-08

0.119653802

-0.922073498

105

378.15

0.002644453

90.68

9.068E-08

0.125887072

-0.900018867

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

Slope                                      -3606.821
Standard deviation in slope     57.662

Intercept                                         8.638
Standard deviation in intercept  0.154

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3606.821/temp(K) + 8.638

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.460.

Run 10 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 7 to 10.


Conclusions:
The vapour pressure of the test item has been determined to be 5.1 x 10-4 Pa at 25ºC.
Executive summary:

Method

The vapour pressure was determined using a vapour pressure balance withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

Run

Log10[Vp(25ºC)]

7

-3.059

8

-3.366

9

-3.270

10

-3.460

Mean

-3.289

Vapour Pressure

5.140 x 10-4 Pa

The test item did not change in appearance under the conditions used in the determination.

Conclusion

The vapour pressure of the test item has been determined to be 5.1 x 10-4 Pa at 25ºC.

Description of key information

The vapour pressure of the test item has been determined to be 5.1 x 10E-4Pa at 25ºC.

Key value for chemical safety assessment

Vapour pressure:
0.001 Pa
at the temperature of:
25 °C

Additional information

INTRODUCTION

Hazardous physico-chemical properties of the test item have been determined. Methods employed are designed to be compatible with Commission Regulation (EC) No 440/2008 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties and the current OECD Guidelines for Testing of Chemicals.

Method

The vapour pressure was determined using a vapour pressure balance withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

Run

Log10[Vp(25ºC)]

7

-3.059

8

-3.366

9

-3.270

10

-3.460

Mean

-3.289

Vapour Pressure

5.140 x 10-4Pa

The test item did not change in appearance under the conditions used in the determination.

Conclusion

The vapour pressure of the test item has been determined to be 5.1 x 10-4Pa at 25ºC.